Answer:
(2,0)
Step-by-step explanation:
point D is on point (2,0)
that is what it means
Answer:
a) True
b) False
c) False
d) False
e) True
Step-by-step explanation:
a) Each basis of V has four vectors. Then any set of 5 vectors must be linear dependent (LD).
b) Suppose that 
is a basis of V. Considere the set 
where 
are scalars. The set has 5 vectors but 
because 
is not belong to A and is linear independent of 
c) Suppose that is a basis of V. Considere the set 
where 
are scalars. A has four nonzero vectors but isn't a basis because is a LD set.
d) Suppose that is a basis of V. Considere the set 
where are scalars. A has 3 nonzero vectors but isn't a basis because is a LD set.
e) Since any basis of V must have 4 elements, then a set of three vectors cannot generate V.
It is necessary for a coordinate to be in quadrant III that both x and y coordinate have to be negative. For e.g (-2,-2) have both x and y coordinate negative , so it is in quadrant III , where as (2,-2) or(-2,2) are not in quadrant III. In the given question C (-a,-a) have both x and y coordinates negative. SO C is in third quadrant and the correct option is C .
Answer:
f(x) = x² - 10x + 24
Step-by-step explanation:
The quadratic function has a graph that passes through the points (4,0) and (6,0).
Therefore, the graph has two x-intercepts at x = 4 and x = 6 and those are the roots of the equation.
So, (x - 4) and (x - 6) are two factors of the quadratic equation.
Then we can write the equation as
f(x) = (x - 4)(x - 6)
⇒ f(x) = x² - 4x - 6x + 24
⇒ f(x) = x² - 10x + 24
Hence, this is the required quadratic function in standard form. (Answer)
which follows from the definition for expected value,
where
is the probability density function for
.
