The value for n is 
<h3>solving for n</h3>
<u>given data</u>
10n^{2} - 12 = -8
making n the subject of the formula
10n^{2} = -8 + 12
10n^{2} = 4
divide through by 10
n^{2} = 4 / 10
finding the square root of both sides
n = square root ( 4 / 10 )

n = 0.632 or 
Read more the subject of formula here: brainly.com/question/21140562
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Answer: The nth term of a geometric progression is Tn = ar^(n-1)
A. 12
B. 3.6
C. -3/4
D. 0.6
Step-by-step explanation:
The nth term of a geometric progression is Tn = ar^(n-1)
Where Tn= nth term
a = first term
r = common ratio
n = number
A. a6 = (2*6) = 12
B. a6 = (0.6*6) = 3.6
C. a6 = (-1/8*6) = -3/4
D. a6 = (0.1*6) = 0.6
7 is in the ones place value.
9 is in the tens place value.
Hope this helps.
-Benjamin
So 3+1=4 then you do the half you know 2 hlafs=whole so thats 1 and 4+1=5
5 is the answer
Answer:
a) 
b) n = 381
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?
When we do not know the proportion, we use
, which is when we are going to need the largest sample size.
The sample size is n when M = 0.01.






b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?
Now we have that
. So






Rouding up
n = 381