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timofeeve [1]
3 years ago
9

Which equation correctly shows the angle relationships for the given figure?

Mathematics
1 answer:
pshichka [43]3 years ago
8 0

Answer:

a

Step-by-step explanation:

(3x-14)+9x=90, thus,

((3x-14)+9x)+90=180

90+90=180

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Pls help extra points and mark brainlist
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Answer:

B. C. and E.

Step-by-step explanation:

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3 years ago
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(a) Using computer or tables (or see Chapter 7, Section 11), verify that P[infinity] n=1 1/n2 = π2/6=1.6449+, and also verify th
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i don't really know soryyyy

Step-by-step explanation:

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3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
wo quantities are related, as shown in the table: x y 2 2 4 5 6 8 8 11 Which equation best represents the relationship?
balandron [24]
These quantities are related linearly with slope
3/2. without knowing the answer choices I can only give you examples of equations that fit

y-2=3/2(x-2). or y=3/2(x) -1

etc
7 0
3 years ago
A store had a sale where you could get 7 bags of cashews for $2. If you wanted to buy 70 bags, how much would it cost?
expeople1 [14]

Answer:

$20

Step-by-step explanation:

7 x __=70

2 x ____=___

7 x 10 = 70

2 x 10

=20

6 0
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