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Alex
3 years ago
6

Find three consecutive integers whose sum is -21. 2. find three consecutive odd integers whose sum is 144. 3. the sum of three c

onsecutive even integers is 48. what are the numbers?
Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
Easy way
-21÷3=-7 which is the exact center so
-6, -7, -8

Equation
x + (x+1) + (x+2) = -21
3x + 3 = -21
3x=-24
x=-8
x+1=-7
x+2=-6

2. Consecutive Odd Integers
X, X+2, X+4

X + (X+2) + (X+4) = 144
3X+6=144
3X=144-6=138
X = 138/3 = 46 .....There are no 3 odd Integers that can equal an even integer

3. 3 consecutive even number x, x+2, x+4

X + (X+2) + (X+4) = 48
3X+6=48
3X=48-6=42
X=42/3=14
14, 16, 18
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Answer:

d = \sqrt{14} = 3.74...

Step-by-step explanation:

To find the distance between (8, -3, 4) and (6, -4, 1), use the distance formula for (x,y,z) points. It is very similar to (x,y) points.

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2 + (z_2 - z_1)^2} \\d = \sqrt{(8 - 6)^2 + (-3--4)^2 + (4-1)^2} \\d = \sqrt{(2)^2 + (1)^2 + (3)^2} \\d = \sqrt{4 + 1 + 9}\\ d = \sqrt{14} = 3.74...

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Step-by-step explanation:

4 0
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Plz help and I will give brainliest
DiKsa [7]

Answer:

a. f<g is one of them. On the number line, g is closest to 0, meaning it is greater than f.

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Step-by-step explanation:

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LekaFEV [45]

Answer: y-1=\dfrac32(x+3)

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = \dfrac{d-b}{c-a}

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)

Required equation: y-1=\dfrac32(x+3)

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