Question

Find the value of the variable. B2%7D" id="TexFormula1" title="\frac{15}{11}x=(5\sqrt{15})^{2}" alt="\frac{15}{11}x=(5\sqrt{15})^{2}" align="absmiddle" class="latex-formula">

Answer 1

Heya!

I'm going to skip the decimal part with the square root since its a non-terminating decimal.

Steps to solve:

$\frac{15}{11}x = (5\sqrt{15})^2$

~Simplify

$\frac{15}{11}x = 375$

~Multiply $\frac{11}{15}$ to both sides

$\frac{15}{11}x * \frac{11}{15} = 375 * \frac{11}{15}$

~Simplify

→ $x = 275$ ←

Best of Luck!

Answer 2

Hey there!

Your answer is x = 275.

First let's simplify the right side of the equation. I'm just going to put it into a calculator because it will get messy with decimals. But know that the operations inside parenthesis are done before squaring the value.

15 is square rooted (is that a word?), multiplied by 5, and after that it is squared. This is equal to 375.

Now we have the following:

$\frac{15}{11} x = 375$

Divide each side of the equation by $\frac{15}{11}$.

x = 275

The value of x is 275.

Hope this helps!