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3 years ago

Can someone pls help me?

Mathematics

1 answer:

Alexxandr [17]3 years ago

8 0

Your answer is 2,401

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Find the area of the triangle.

Archy [21]

Answer:

Area= 80 in square

Step-by-step explanation:

h=8

b=20

formula= b*h/2

so, 8*20/2

Area= 80 in square

7 0

2 years ago

Solve x: 60 pts if u can figure it out and the first one gets brainiest answer

jenyasd209 [6]

Answer:

11.65

Step-by-step explanation:

3x+99x=102x

1188/102=11.65

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2 years ago

Read 2 more answers

X + 1/2 = 17 need help fast

Paha777 [63]

Answer:

x=16.5

Step-by-step explanation:

-1/2 on both sides

17-0.5 or 1/2=16.5

7 0

3 years ago

Read 2 more answers

given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

3 years ago

PLEASE help due today Geometry

irina1246 [14]

$\\ \sf\Rrightarrow \dfrac{15}{20}=\dfrac{21}{28}$

$\\ \sf\Rrightarrow \dfrac{1}{4}=\dfrac{1}{4}$

Hence they are similar

<A=<H
And ratio of sides are same

Hence both triangles are similar by SAS property

$\\ \sf\Rrightarrow ∆KDH\sim ∆ABD$

8 0

2 years ago