Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
Answer:
there is nothing on here
Step-by-step explanation:
f(x) - n - move the graph n units down
f(x) + n - move the graph n units up
f(x - n) - move the graph n units right
f(x + n) - move the graph n units left
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<h3>Answer: g(x) = x² - 3</h3>
Step-by-step explanation:
Answer: A pot of 2400ml
Step-by-step explanation: Ok, mei has 8 jars, and each jar has 300ml of soup, so the total amount of soup is 8 times 300ml
N = 8*300ml = 2400ml
So the smallest pot that mei can use to heat the soup is a pot that has exactly that volume. 2400ml, (discarding the fact that the volume of the soup will change as it is heated up)
