Hi!
![6x-8=4x](https://tex.z-dn.net/?f=6x-8%3D4x)
![6x-8+8=4x+8](https://tex.z-dn.net/?f=6x-8%2B8%3D4x%2B8)
![6x=4x+8](https://tex.z-dn.net/?f=6x%3D4x%2B8)
![6x-4x=4x+8-4x](https://tex.z-dn.net/?f=6x-4x%3D4x%2B8-4x)
![2x=8](https://tex.z-dn.net/?f=2x%3D8)
![\frac{2x}{2}=\frac{8}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7B2%7D%3D%5Cfrac%7B8%7D%7B2%7D)
![x=4](https://tex.z-dn.net/?f=x%3D4)
Explanation:<em> </em><u><em>First you had to add by 8 from both sides. Then simplify, you can subtract by 4x from both sides. Simplify again, you can divided by 2 and it gave us 2x/2=8/2. And the answer is x=4 is the right answer. Hope this helps! And thank you for posting your question at here on Brainly. And have a great day. -Charlie</em></u>
Answer:
I think it's A) 4
Step-by-step explanation:
I'm pretty sure it has 4 terms in standard form
Answer:
0.4375
Step-by-step explanation:
Lets say that X is the random varaible that determine the arrival time of Bob and Y the random variable that determine the arrival time of Alice. Bot X and Y are Independent random variables with uniform [0,1] distribution. 15 minutes is the quarter of an hour, so we want to calculate P(|X-Y|) < 0.25.
Note that P(|X-Y| < 0.25) = P(|X-Y| < 0.25 | X ≥ Y) * P(X≥ Y) + P(|X-Y| < 0.25 | Y ≥ X) * P(Y ≥ X) = P(X-Y < 0.25 | X ≥Y) * P(X≥Y) + P(Y-X < 0.25 | Y≥X)*P(Y ≥ X).
For a simmetry argument, that expression is equivalent to 2*P(Y-X < 0.25 | Y≥X)*P(Y ≥ X) = 2*P(0 < Y-X < 0.25). The region 0 < Y-X < 0.25 is, for X between 0 and 0.75, a parallelogram, of base 0.75 and height 0.25, and for X between 0.75 and 1, it is a Triangle of base and height equal to 0.25. Therefore P(0 < Y-X < 0.25) = 0.25*0.75 + 0.25² * 0.5 = 7/32. Hence 2*P(0 < Y-X < 0.25) = 14/32 = 0.4375.
They will meet for lunch with probability 0.4375
Answer:
9 feet away
Step-by-step explanation:
40²+b²=41²
1600+b²=1681
b²=81
b=9
Answer:
The answer will be ![\frac{1}{256}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B256%7D)
Step-by-step explanation:
We have given that
And we have to find the value of ![(4x)^{\frac{-4}{3}}](https://tex.z-dn.net/?f=%284x%29%5E%7B%5Cfrac%7B-4%7D%7B3%7D%7D)
As
![x=(64)^{\frac{2}{3}}=(4^3)^\frac{2}{3}=4^2=16](https://tex.z-dn.net/?f=x%3D%2864%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D%284%5E3%29%5E%5Cfrac%7B2%7D%7B3%7D%3D4%5E2%3D16)
So the value of x = 16
Now we have to find the value of ![(4x)^{\frac{-4}{3}}](https://tex.z-dn.net/?f=%284x%29%5E%7B%5Cfrac%7B-4%7D%7B3%7D%7D)
So ![(4\times 16)^{\frac{-4}{3}}=(64)^{\frac{-4}{3}}=(4^3)^{\frac{-4}{3}}=4^{-4}=\frac{1}{4^4}=\frac{1}{256}](https://tex.z-dn.net/?f=%284%5Ctimes%2016%29%5E%7B%5Cfrac%7B-4%7D%7B3%7D%7D%3D%2864%29%5E%7B%5Cfrac%7B-4%7D%7B3%7D%7D%3D%284%5E3%29%5E%7B%5Cfrac%7B-4%7D%7B3%7D%7D%3D4%5E%7B-4%7D%3D%5Cfrac%7B1%7D%7B4%5E4%7D%3D%5Cfrac%7B1%7D%7B256%7D)