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vaieri [72.5K]
3 years ago
15

Use the equation tool to complete the table y=-670+33(x)

Mathematics
2 answers:
Alja [10]3 years ago
7 0

Real Question :

Now Try Working With A New Function.

Use The Equation Tool To Complete Both Tables.

\left[\begin{array}{ccc}Table A\\x&y\\25&155\\30&320\\35&485\\40&650\\45&?\end{array}\right] \left[\begin{array}{ccc}Table B\\x&y\\40&650\\41&683\\42&716\\43&749\\44&?\end{array}\right]

\left[\begin{array}{ccc}y=-670+33(25)\\y=-670+33(30)\\y=-670+33(35)\\y=-670+33(40)\\?=-670+33(45)\end{array}\right] \left[\begin{array}{ccc}y=-670+33(40)\\y=-670+33(41)\\y=-670+33(42)\\y=-670+33(43)\\?=-670+33(44)\end{array}\right]

\left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(45)\end{array}\right] Plug It In \left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(44)\end{array}\right]

\left[\begin{array}{ccc}33(x)Or33(45)\\1485\end{array}\right] Multiply \left[\begin{array}{ccc}33(x)Or33(44)\\1452\end{array}\right]

\left[\begin{array}{ccc}y=-670+1485\\y=815\end{array}\right] Simplify \left[\begin{array}{ccc}y=-670+1452\\y=782\end{array}\right]

\left[\begin{array}{ccc}y=-670+33(x)\\y=-670+33(45)\\y=-670+1485\\y=815\end{array}\right] Answers \left[\begin{array}{ccc}y= -670 + 33 (x)\\y = -670 + 33 (44)\\y = -670 +1452\\y=782\end{array}\right]

hjlf3 years ago
5 0

Solution:

we have been asked to Use the equation tool to complete the table .

The given equation is y=-670+33x

As we can see the Table is already filled , just one place need to fill.

So we will substitute the value of x from the table in the given equation and we will work out the value of y.

From table we have x=45.

y=-670+33*45\\
\\
y=-670+1485\\
\\
y=815\\

Hence required value for the blank space in the table is 815.



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Svet_ta [14]

Slope Formula - (y² - y¹) / (x² - x¹)

(1, 7)

x¹ = 1

y¹ = 7

(-4, -8)

x² = -4

y² = -8

-8 - 7 = -15

-4 - 1 = -5

Simplify - -15/-5

-15/5 = -3

Your answer is -3.

Hope this Helps!!


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3 years ago
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When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

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<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
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\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
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Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
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