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Lera25 [3.4K]
3 years ago
5

Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what would be the

appropriate increments? Reporting periods Sales Jan.–Mar., 2010 $100,000 Apr.–Jun., 2010 $55,000 Jul.–Sep., 2010 $45,000 Oct.–Dec., 2010 $110,000 Jan.–Mar., 2011 $330,000 Apr.–Jun., 2011 $800,000 Jul.–Sep., 2011 $242,000 Oct.–Dec., 2011 $150,000

Mathematics
1 answer:
11111nata11111 [884]3 years ago
5 0
Given the data, we would label the x-axis "months" and which means we will place the months on the x-axis, and the amounts will be graphed with increments of 100,000. 

Hope this Helped!.
Note: I included an example of what  the graph would look like if I made one using the data.

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Suppose that a computer chip company has just shipped computer chips to a computer company.​ Unfortunately, of the chips are def
Varvara68 [4.7K]

Answer:

(a) 0.0000245

(b) 0.000025

Step-by-step explanation:

The complete question is:

Suppose that a computer chip company has just shipped 10,000 computer chips to a computer company. Unfortunately, 50 of the chips are defective. (a) Compute the probability that two randomly selected chips are defective using conditional probability. (b) There are 50 defective chips out of 10,000 shipped. The probability that the first chip randomly selected is defective is  50 /10,000  = 0.005.  Compute the probability that two randomly selected chips are defective under the assumption of independent events.

Solution:

(a)

In this case we need to compute the conditional probability of selecting two defective chips, i.e. the selection of the second defective chip is dependent on the first defective chip.

The probability of selecting the first defective chip is:

P(1D)=\frac{50}{10000}=0.005

Now there are 9999 chips left and 49 defective chips among them.

The probability of selecting the second defective chip is:

P(2D)=\frac{49}{9999}=0.0049

Compute the probability that two randomly selected chips are defective using conditional probability as follows:

P (Two defective chips) =P(1D)\times P(2D)=0.005\times 0.0049=0.0000245

Thus, the answer is 0.0000245.

(b)

Compute the probability that two randomly selected chips are defective under the assumption of independent events as follows:

The above statement implies that the selection was done with replacement.

The probability is:

P (Two defective chips) =P(1D)\times P(2D)

                                      =\frac{50}{10000}\times \frac{50}{10000}\\\\=0.005\times 0.005\\\\=0.000025

Thus, the probability that two randomly selected chips are defective under the assumption of independent events is 0.000025.

6 0
3 years ago
S over 4= -3.2 find the value of s
ryzh [129]

Answer:

s = - 12.8

Step-by-step explanation:

Given

\frac{s}{4} = - 3.2 ( multiply both sides by 4 to clear the fraction )

s = 4 × - 3.2 = - 12.8

7 0
3 years ago
Read 2 more answers
Part A
Firlakuza [10]

Step-by-step explanation:

They told about a place in the Andes Mountains where people worshipped chieftains covered in gold…”

3 0
2 years ago
Five students wrote a mathematics test. The average mark was 68. If the marks for four of the students were 75, 62, 84 and 53, t
konstantin123 [22]

Answer:

66

Step-by-step explanation:

Use the formula for the mean of a set of numbers:

                  sum of the numbers

average = --------------------------------

                     count of numbers

Here we know that the average mark was 68, so we can write:

               

                           75 + 62 + 84 + 53 + x

average = 68 = ----------------------------------

                                           5

or                            274 + x

                  68 = -------------------

                                    5

Solving for x, we multiply both sides by 5:     340 = 274 + x.

Subtracting 274 from both sides effectively isolates x:

 340 = 274 + x

- 274    -274

------------------------

  66      =    x

The fifth student's mark was 66.

4 0
3 years ago
Divide f(x) by d(x), and write a summary statement in the form indicated.
lukranit [14]
( x^4 - 4 x³ + 2 x² - 4 x + 1 ) : ( x² + 1 )   =  x² - 4 x + 1
- x^4             - x²
------------------------
          - 4 x³ + x² - 4 x
            4 x³        + 4 x
         -----------------------
                      x²  + 1
                   - x²   - 1
                ----------------
                   R ( x ) = 0
( x^4 - 4 x³ + 2 x² - 4 x + 1) =  ( x² + 1 ) ( x² - 4 x + 1 )
3 0
3 years ago
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