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3 years ago

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

8 0

<span>A. 3(6)-1/2(6)+1 this is the answer

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Alex777 [14]3 years ago

6 0

Answer:

$\frac{3(6)-1}{2(6)+1}\text{ or }\frac{18-1}{12+1}\text{ or }\frac{17}{13}$

Step-by-step explanation:

Given functions,

$r(x) = 3x -1------(1)$

$s(x) = 2x + 1-----(2)$

$\because \frac{r}{s}(6)=\frac{r(x)}{s(x)}$

From equation (1) and (2),

$\frac{r}{s}(x)=\frac{3x-1}{2x+1}$

Put x = 6,

$\frac{r}{s}(6) = \frac{3(6)-1}{2(6)+1}=\frac{18-1}{12+1}=\frac{17}{13}$

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3 years ago

Initially, there were equal amount of roses and tulips at a store. Each bouquet was made with 3 roses and 4 tulips. After the bo

egoroff_w [7]

Answer:

12 bouquets

Step-by-step explanation:

Let there be x number of roses and x number of tulips initially at the store. Each bouquet was made with 3 roses and 4 tulips. Assume that y bouquets were made in total.

If each bouquet was made with 3 roses and 4 tulips, then y bouquets will be made with 3y roses and 4y tulips.

After the bouquets were all made, there were 30 roses and 18 tulips left in the store. This means, if we subtract number of roses that were used in bouquets from total number of roses, the result must be 30. Likewise, for tulips the result would be 18. This can be represented as:

x - 3y = 30 Equation 1

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Subtracting Equation 2 from Equation 1, we get:

x - 3y - (x - 4y) = 30 - 18

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3 years ago

Read 2 more answers

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3 years ago

A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de

marin [14]

Answer:

$\frac{23}{4}$ feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 $\frac{1}{2}$ feet

= $\frac{5}{2}$ feet

The depth of the fish to its initial position at 4:00 pm = 3 $\frac{1}{4}$ feet

= $\frac{13}{4}$ feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

= $\frac{5}{2}$ + $\frac{13}{4}$

= $\frac{10 + 13}{4}$

= $\frac{23}{4}$

The position of the fish with respect to the water's surface at 4:00 pm is $\frac{23}{4}$ feet.

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3 years ago

Find the midpoint of (1,-7),(1, 11)

sergij07 [2.7K]

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