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alexandr402 [8]
2 years ago
8

The equation of a circle is given as x2+ax+y2+by=c where a, b, and c are constants. The radius of the circle is given by the exp

ression
(a2)2+(b2)2+c

a+b+c

(a2)2+(b2)2

c√
Mathematics
2 answers:
Lady bird [3.3K]2 years ago
7 0
B because if the circle has a radius of x2 the 1/2 of that would be a+c bringing in c to become abc or a+b+c
sergeinik [125]2 years ago
7 0

Answering actually A

Step-by-step explanation:

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Vanyuwa [196]

Answer:

I think it's 3:5

Step-by-step explanation:

I really don't understand your question

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2 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
3 years ago
Read 2 more answers
Find the inverse g(x)=x/5-6
STALIN [3.7K]
Interpreted: g(x) = \frac{x}{5} - 6
Let y = g(x)
y = \frac{x}{5} - 6
x = \frac{y}{5} - 6 (Interchange the x and y-values)

\frac{y}{5} = x + 6 (Solve for y)
y = 5(x + 6)

\therefore g^{-1}(x) = 5(x + 6)
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Purple paint is
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Answer:

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Step-by-step explanation:

3 0
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Answer:

Step-by-step explanation:A

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3 years ago
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