Kevin and Randy Muise have a jar containing 80 coins, all of which are either quarters or nickels. The total value of the coins in the jar is $11.80. How many of each type of coin do they have?
1 answer:
Answer:
39 quarters and 41 nickels Step-by-step explanation:
Let the number of quarters be x and nickels be y.
<u>Given:</u>
Quarter is 25 cents Nickel is 5 cents Number of coins is 80 Total amount is $11.80 = 1180 cents <u>We have equations:</u>
x + y = 80 25x + 5y = 1180 <u>Solve the system by elimination, subtract 5 times the first equation from the second one:</u>
25x + 5y - 5x - 5y = 1180 - 80*5 20x = 780 x = 780/20 x = 39 <u>Find the value of y:</u>
39 + y = 80 y = 80 - 39y = 41 <u>Verify:</u>
25*39 + 5*41 = 975 + 205 = 1180
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Heyyyyy
Hope this helps!
~Nadia~
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