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erma4kov [3.2K]

3 years ago

12

Given a square with two vertices of one side located at (-5. -3) and (-5, 12), in square units what is its area?

2 answers:

Zanzabum3 years ago

8 0

Answer:

225

Step-by-step explanation:

Since the side length of the square is 15 units, a square has sides of the same length, therefore the other side lengths are also 15 units. A = b*h so 15*15=225

givi [52]3 years ago

4 0

Answer:

4. 225

Step-by-step explanation:

The distance between points (-5, -3) and (-5, 12) is the length of the side of the square. Since both points have an x-coordinate of -3, they lie on the same vertical line. The distance between them is |12 - (-3)| = |12 + 3| = |15| = 15. The side measures 15 units.

area = side^2

area = 15^2 = 225

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2 years ago

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Examples:

case-1:

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We can simplify it

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3 years ago