Given a square with two vertices of one side located at (-5. -3) and (-5, 12), in square units what is its area?

Mathematics

2 answers:

Zanzabum4 years ago

8 0

Answer:

225

Step-by-step explanation:

Since the side length of the square is 15 units, a square has sides of the same length, therefore the other side lengths are also 15 units. A = b*h so 15*15=225

givi [52]4 years ago

4 0

Answer:

4. 225

Step-by-step explanation:

The distance between points (-5, -3) and (-5, 12) is the length of the side of the square. Since both points have an x-coordinate of -3, they lie on the same vertical line. The distance between them is |12 - (-3)| = |12 + 3| = |15| = 15. The side measures 15 units.

area = side^2

area = 15^2 = 225

You might be interested in

What's 89452×636428÷36?

Whitepunk [10]

,,,,,,,,,,,............,.............................................

7 0

3 years ago

An automobile manufacturer obtains the microprocessors used to regulate fuel consumption in its automobiles from three microelec

Anastaziya [24]

Answer:

The probability that a randomly selected automobile manufactured by the company will have a defective microprocessor is 6.2 %.

Step-by-step explanation:

Given:

The probability of getting a microprocessor from firm A is, $P(A)=45\%=0.45$

The probability of getting a microprocessor from firm B is, $P(B)=30\%=0.30$

The probability of getting a microprocessor from firm C is, $P(C)=25\%=0.25$

Now, let event D be having a defective microprocessor at random.

So, as per the question,

Probability of producing a defective microprocessor from firm A is, $P(D/A)=6\%=0.06$

Probability of producing a defective microprocessor from firm B is, $P(D/B)=7\%=0.07$

Probability of producing a defective microprocessor from firm C is, $P(D/C)=5.5\%=0.055$

Now, probability of having a defective microprocessor when selected at random is given as:

$P(D)=P(A)\cdot P(D/A)+P(B)\cdot P(D/B)+P(C)\cdot P(D/C)\\P(D)=(0.45\times 0.06)+(0.30\times 0.07)+(0.25\times 0.055)\\P(D)=0.027+0.021+0.01375\\P(D)=0.06175\ or\ P(D)=0.06175\times 100\approx 6.2\%$