9514 1404 393
Answer:
9.5°, yes
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
The distance opposite the angle of elevation is the plane's height, 500 m. The distance adjacent to the angle of elevation is the horizontal distance to the plane, 3 km = 3000 m. Then the angle is found from ...
tan(α) = 500/3000 = 1/6
α = arctan(1/6) ≈ 9.46°
The plane is approaching at an angle of 9.46°. It is safe to land, since that angle is less than 15°.
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<em>Additional comment</em>
The usual descent angle for most commercial air traffic is 3°. Some airport geography demands it be different (steeper). A higher descent angle can put undue stress on the landing gear.
Answer:
x > 5
Step-by-step explanation:
3 ( 2x - 4 ) > 2 ( x + 4 )
6x - 12 > 2x + 8
4x > 20
x > 5
Find the average :8.4+7.5+12.9+10.6 divided by four
Answer:
(2x + 5) ( x + 5)
Step-by-step explanation:
2x² + 15 + 25
2x² + 10x + 5x + 25
2x( x + 5) + 5( x + 5)
(2x + 5) (x + 5)
