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Papessa [141]
2 years ago
14

The general form of a circle is given as x^2 + y^2 + 4x - 12y + 4 = 0.

Mathematics
1 answer:
stepan [7]2 years ago
7 0
If you can rewrite the formula as (x-a)² + (y-b)² = r², the center is at (a,b) and the radius is r.

If you work out this equation, and map it to the original, you will find that the +4x term hints that a = 2 (double product) and -12y hints that b=-6, and r=6.

So, the formula can be written as (x+2)² + (y-6)² = 6² and the center is at (-2,6) and the radius is 6.
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Yuki888 [10]

Answer:

5a -4

Step-by-step explanation:

Given

(2a + 3) + (3a - 7) ← remove parenthesis

= 2a + 3 + 3a - 7 ← collect like terms

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Find the x- and y- intercepts of the line with the given equation <br><br> -6x+8y=-36
Likurg_2 [28]

Answer:

Y int at

(

0

,

3

2

)

X int at

(

3

,

0

)

Step-by-step explanation:

The line is easier to visualize when the equation is in slope-intercept form:

4

x

+

8

y

=

12

Divide each side by 4:

x

+

2

y

=

3

2

y

=

−

x

+

3

y

=

−

1

2

x

+

3

2

Y-intercept (plug in 0 for x):

y

=

−

1

2

(

0

)

+

3

2

y

=

3

2

X-intercept (plug in 0 for y):

0

=

−

1

2

x

+

3

2

−

3

2

=

−

1

2

x

x

=

3

5 0
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