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Papessa [141]
2 years ago
14

The general form of a circle is given as x^2 + y^2 + 4x - 12y + 4 = 0.

Mathematics
1 answer:
stepan [7]2 years ago
7 0
If you can rewrite the formula as (x-a)² + (y-b)² = r², the center is at (a,b) and the radius is r.

If you work out this equation, and map it to the original, you will find that the +4x term hints that a = 2 (double product) and -12y hints that b=-6, and r=6.

So, the formula can be written as (x+2)² + (y-6)² = 6² and the center is at (-2,6) and the radius is 6.
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Which is a negatively skewed distribution?<br> HELP PLEASE
zlopas [31]

Answer:

i think its c

Step-by-step explanation:i think its c because it has dot on the very left

5 0
2 years ago
A) Find the value of 3x – 2 when x = 4<br>b) Find the value of 5x + 6 when x = -2​
Svetradugi [14.3K]

Answer: 10 and -4

Step-by-step explanation:

3x - 2 Plug in 4 for x

3(4) - 2 = 12 - 2 = 10

5x + 6. Plug in -2 for x

5(-2) + 6 = -10 + 6 = -4

8 0
3 years ago
If 70g is 100%.... 48g is taken away... what is the percentage of the remaining 22g. Rounded to the nearest whole number?
Ivenika [448]

we are given with 70 grams and is said that 48 grams is taken away. This is equal to 22 grams. To find the mass percentage, we divide the remaining mass and divide by the total mass. The remaining 22 grams is equal to 22/70 * 100 percent equal to 31.43 percent. 
8 0
3 years ago
Kendall was able to score 368 points on 32 games. create a unit rate for this information.
Lesechka [4]

(368 points) / (32 games)  =  11.5 points/game

(32 games) / (368 points) = 0.08696 game/point

8 0
3 years ago
What is the value of C in the matrix equation below?
lara [203]

Given:

The matrix equation is:

\begin{bmatrix}-18&3&5\end{bmatrix}-C=\begin{bmatrix}-22&1&12\end{bmatrix}

To find:

The value of matrix C.

Solution:

Let A=\begin{bmatrix}-18&3&5\end{bmatrix},B=\begin{bmatrix}-22&1&12\end{bmatrix}. Then the given equation can be rewritten as

A-C=B

-C=B-A

C=-(B-A)

C=A-B

On substituting the values of the matrices, we get

C=\begin{bmatrix}-18&3&5\end{bmatrix}-\begin{bmatrix}-22&1&12\end{bmatrix}

C=\begin{bmatrix}-18-(-22)&3-1&5-12\end{bmatrix}

C=\begin{bmatrix}-18+22&2&-7\end{bmatrix}

C=\begin{bmatrix}-4&2&-7\end{bmatrix}

Therefore, the correct option is C.

6 0
2 years ago
Read 2 more answers
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