Answer:
Option A: print("The total is %0.5f" % total)
Explanation:
To ensure the value is rounded to a precision of 5 digits, we have to create a formatted string which is %0.5f. The <em>.5</em> denotes five decimal places and <em>f </em>refers to float data type.
Next, we use the <em>%</em> operator again and followed with the variable <em>total</em>. The % is used as a string modulo operator that will interpolate the value held by the the variable <em>total </em>in the formatted string that we create previously. The interpolated value will be rounded to 5 decimal places. For example, if
total = 256.786789
The output will be 256.78679
Answer:
To convert hexadecimal number 11BA to decimal, follow these two steps:
Start from one's place in 11BA : multiply ones place with 16^0, tens place with 16^1, hundreds place with 16^2 and so on from right to left
Add all the product we got from step 1 to get the decimal equivalent of 11BA.
Using the above steps, here is the work involved in the solution for converting 11BA to decimal number (Don't forget that we start from ones place to so on...)
Decimal equivalent of "A" = (A) 10 × 16^0 = 10
Decimal equivalent of "B" = (B) 11 × 16^1 = 176
Decimal equivalent of "1" = 1 × 16^2 = 256
Decimal equivalent of "1" = 1 × 16^3 = 4096
Decimal equivalent of "11BA" = 409625617610
11BA = 4538
Here is the final answer, The hexadecimal number 11BA converted to decimal is therefore equal to:
4538
Answer:
if full_admission_price = f and discount_amount = d
=> Price of a discount admission = d/f
total_weight
quantity
weight of one item = total_weight/quantity
for i in range(80, 18, -2):
print(i, end=' ')
Explanation:
The first two questions are just mathematical to get a single quantity given some relationship. So, its basically division
For the python code, I used the python's range function which takes in three arguments. The first one is the starting value, the second one is the terminating value which is the number before the terminating value and the last one specifies the common difference popularly known as step in the language. Since the step is 2, only even numbers are printed out. In the print function, I made use of the end keyword specifying a space (' ') as the end. This ensures that the print is done in the same line with a space seperating them. Without that specification, each result will printed in a newline
C.apple domain is to use the personal sharing files from one computer to another computer
Using the knowledge in computational language in C++ it is possible to write a code that Find the Average of the sum of prime numbers between 1 to any given number
<h3>Writting in C++ code:</h3>
<em />
<em>#include <iostream></em>
<em>using namespace std;</em>
<em>bool isPrime(int n){</em>
<em> for(int i = 2; i < n/2; i++){</em>
<em> if(n%i == 0){</em>
<em> return false;</em>
<em> }</em>
<em> }</em>
<em> return true;</em>
<em>}</em>
<em>int findPrimeSum(int n){</em>
<em> int sumVal = 0;</em>
<em> for(float i = 2; i <= n; i++){</em>
<em> if(isPrime(i))</em>
<em> sumVal += i;</em>
<em> }</em>
<em> return sumVal;</em>
<em>}</em>
<em>int main(){</em>
<em> int n = 15;</em>
<em> cout<<"The sum of prime number between 1 to "<<n<<" is "<<findPrimeSum(n);</em>
<em> return 0;</em>
<em>}</em>
See more about C++ code at brainly.com/question/19705654
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