1) 10 3/10
3) 2 1/2
4) 10 2/3
6) 6 1/2
7) 4 3/4
9) 1 8/9
10) 1 5/6
Answer:
6966
Step-by-step explanation:
7740*10%=774
7740-774=6966
If inspection department wants to estimate the mean amount with 95% confidence level with standard deviation 0.05 then it needed a sample size of 97.
Given 95% confidence level, standard deviation=0.05.
We know that margin of error is the range of values below and above the sample statistic in a confidence interval.
We assume that the values follow normal distribution. Normal distribution is a probability that is symmetric about the mean showing the data near the mean are more frequent in occurence than data far from mean.
We know that margin of error for a confidence interval is given by:
Me=
α=1-0.95=0.05
α/2=0.025
z with α/2=1.96 (using normal distribution table)
Solving for n using formula of margin of error.

n=
=96.4
By rounding off we will get 97.
Hence the sample size required will be 97.
Learn more about standard deviation at brainly.com/question/475676
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The given question is incomplete and the full question is as under:
If the inspection division of a county weights and measures department wants to estimate the mean amount of soft drink fill in 2 liters bottles to within (0.01 liter with 95% confidence and also assumes that standard deviation is 0.05 liter. What is the sample size needed?
The answer is A. when you compress horizontally you take it by a factor of 1/a. in this case a=5. 12 is your k value and k decides whether or not you shift up or down, because k is positive or is upward by 12
Answer:
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Step-by-step explanation:
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