At Al's Athletic Club, the monthly membership fee for a student is $25 and the monthly
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The distance of a train from the city depends on the speed, the time of
travel, and direction of motion of the train.
Correct responses:
- Distance Train A is from the city: <u>750 - 75·t</u>
- Distance Train B is from the city: 50·t
- After <u>six</u> hours, the two trains are the same distance from the city
- At that time both trains will be <u>300</u> miles away
1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours
2) At time period, t > 6 hours
3) 250 miles
<h3>Method used to find the above response</h3>Given:
The distance of train A from the city = 750 miles
Speed of train A = 75 mph
Time at which Train B leaves the city = When Train A is 750 miles from the city
Speed of Train B = 50 mph
Solution:
The equations are;
- Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
- Distance of Train B from the city is <u>x₂ = 50·t</u>
When the train are the same distance from the city, we have;
750 - 75·t = 50·t
750 = 50·t + 75·t = 125·t
Therefore;
The time it takes the two trains to be the same distance from the city is 6 hours.
Which gives;
- After <u>6</u> hours, the two trains are the same distance from the city.
The distance the trains will be after 6 hours is therefore;
750 - 75 × 6 = 300
The distance of the trains from the city after 6 hours = 300 miles
Therefore, we have;
- At that time both trains will be <u>300</u> miles away
1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>
2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>
3) The distance of Train A from the city after 4 hours is given as follows;
x₁ = 750 - 75 × 4 = 450
x₁ = 450 miles
The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200
x₂ = 200 miles
Therefore;
- The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>
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