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antiseptic1488 [7]
3 years ago
8

What is 3x+5=-8(x+3)

Mathematics
1 answer:
sashaice [31]3 years ago
4 0

Answer:

-29/11

Step-by-step explanation:

i used a calculator lol

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Help ppppppppppppllllllllllllllllsssssssss
iVinArrow [24]

Answer:

The correct option is D ....

Step-by-step explanation:

Angle is ending at the point = (-3, -4)

Signs of both x and y are negative therefore it is in the third quadrant.

To find the the tangent of an angle we have to find  the ratio of the length of the opposite side to the length of the adjacent side.

In this question the opposite side of the angle is of 4 units and the adjacent side of the angle is 3 units.

tanθ = y/x

tanθ = -4/-3

tanθ = 4/3

Thus the correct option is D ....

5 0
4 years ago
Pick the equations that are equal to <br>15-8y=-11​
Black_prince [1.1K]

Answer:

The equations that are equal to 15-8y=-11​ are...

- Number 1

- Number 4

4 0
3 years ago
Read 2 more answers
Answer for -2x-41=5x-6
seraphim [82]

Answer:

x=-5

Step-by-step explanation:

-2x-41=5x-6

-35=7x

-5=x

7 0
3 years ago
Read 2 more answers
Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with
yan [13]

Answer:

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

<em></em>

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, s_A = 12 inches

Height of A, h_A = 8 inches

Side Length of B, s_B = 48 inches

Height of B, h_B = 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

OR

V_B is how many times bigger than V_A ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}

Here, base is square, so:

V=\dfrac{1}{3} \times s^2 \times h

Volume of pyramid A:

V_A=\dfrac{1}{3} \times s_A^2 \times h_A

\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3

Volume of pyramid B:

V_B=\dfrac{1}{3} \times s_B^2 \times h_B

\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

3 0
3 years ago
Five times the number of test tubes in a school’s chemistry lab exceeds three times the number of beakers it has by 660. The sum
vladimir1956 [14]
5t=3b+660....and....2t+5B=450

from the first we can see that the t=(3b+650)/5 and using this value in the second.

(6+1320)/5+5b=450 making all have common denominator.

6b+1320+25b=2250

31b=930

b=30.. and 2t+5b=450

t=150
4 0
4 years ago
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