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Paha777 [63]
3 years ago
9

A bag of marbles contains 8 yellow marbles, 6 blue marbles, 4 red marbles, and 2 green marbles. Two marbles are chosen at random

, WITHOUT replacement. What is the probability a red marble is chosen and then a blue marble?

Mathematics
2 answers:
MatroZZZ [7]3 years ago
6 0

Answer:

6/95

Step-by-step explanation:

First, let's find the total # of outcomes. There are 8+6+4+2 = 20 marbles in the bag. We have 20 options for the first draw, and 19 for the second. 20*19 = 380 total possible outcomes.

Now, let's fin the successful outcomes. There are 4 red and 6 blue marbles, so 4 for the firs tpick and 6 for the second pick. 4*6 = 24 successful outcomes. To find probability, we do successful outcomes/total outcomes, and in this case, that is 24/380, or 6/95. Hope that helps!

ArbitrLikvidat [17]3 years ago
3 0

Answer:

Step-by-step explanation:I don't say you have to mark my ans as brainliest but my friend if it has really helped you plz don't forget to thank me...

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The function y = 3.75 + 2.50(x - 3) can be used to determine the cost in dollars for a uber ride of x miles. What is the rate of
stepan [7]
<span>The cost of each mile is $2.50.

If you simplify the expression given you will get the following.
y = 3.75 + 2.50(x - 3)
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y = 2.50x - 3.75.

Knowing that x is the number of miles and 2.50 is the number being multiplied by, we know that the cost per mile is 2.50. </span>
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3 years ago
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Harrizon [31]

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4. -17

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Step-by-step explanation:

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7 0
2 years ago
Solve for v pls thanks
Ksivusya [100]

Answer:

v = 18

Step-by-step explanation:

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were going to have to get 3 on the other side, so were going to cancel it out and multipliy it because it is a fraction

now we would have 8v = 48*3

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now the equation looks like this 8v = 144

to isolate v we can divide 8 on both sides

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