It takes 7 hours to mow 4 lawns
Therefore every hour, (4 ÷ 7) or 4/7 lawns are mowed. This gives the rate.
For 35 hours, 4/7 x 35 lawns are mowed.
=35 ÷ 7 = 5
= 4 × 5
= 20 lawns
Given that PQ and RS are drawn with KL as tranversal intersecting PQ at M and RS at point N. Angle QMN is congruent to angle LNS because they are alternate to each other. The theorem that Kari can use to show that the meansure of QML is supplementary to the measure of angle SNK is Alternate Exterior Angles Theorem.
This is because angle KNR is equal to QML by alternate exterior angles theorem so is angle MLP and SNK
Answer:
V = 4/3 x pi x r^3
972 x pi= 4/3 x pi x r^3
729 = r^3
The cubic root of 729 is 9 because 9 x 9 x 9 = 729.
The radius is 9 inches, and the diameter is 18 inches.
The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The slope m of the functions give the measure of the rate of change.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
g(x) =
x - 3 ← is in slope- intercept form
with slope m =
= 2.5
Calculate the slope of f(x) using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, - 3.5) and (x₂, y₂ ) = (1, - 1) ← 2 points from the table
m =
= 2.5
Hence
The slopes of g(x) and f(x) are both m = 2.5, thus
The functions increase at the same rate → C
a.
×
A
b.
×
A
c.
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

×
A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

×
A
C. V= 12V
1/R =
=
× 
R =
= 310. 56 Ω

A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
brainly.com/question/14296509
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