There are 180 numbers which are three-digit multiples of 5.
According to the statement
we have to find the three digit numbers which are multiples of 5.
we know that three digit numbers are start from 100 to 999 and in 1 line of counting means 100 to 110 there are 2 numbers are multiples of 5.
Here we use Multiplication method to find the number of digit which are a multiple of 5.
It means there are two numbers which are multiples of 5 in the one line of counting and there are 90 lines of counting from 100 to 999.
So, it means the answer will become
2*90 = 180.
So, There are 180 numbers which are three-digit multiples of 5.
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The answer is 18
You divide 12 buy -2/3
Answer:
It helps you know if the answer is reasonable because when you do the work and get your answer, you can check if it is close to your estimate, and if it is, it is most likely correct. On the other hand if it is not close to the estimate it is most likely wrong, unless you estimated incorrectly.
Step-by-step explanation:
The solution to the algebraic expression is: 23e - 21g - 14j + 32
What are algebraic expressions?
Algebraic expressions are mathematical expressions that contain variables, coefficients, and arithmetic operations such as addition, subtraction, division, and multiplication.
Solving algebraic expressions are an important part of mathematics as it helps to improve the aptitude and solving skills of the students.
From the given information, we have;
23j - 21g + 20e - 13 + 52e - 37j + 45 - 49e
let's rearrange by taking the like terms to the same sides;
= 23j -37j - 21g + 20e + 52e - 49e - 13 + 45
= -14j - 21g + 23e + 32
= 23e - 21g - 14j + 32
Therefore, we can conclude that the solution to the algebraic expression is: 23e - 21g - 14j + 32
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