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3 years ago

Solve for the length of segment AB and BC (round to nearest the tenth)

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

5 0

Answer: AB = 8.4 BC = 12.4
Explanation:
Start of by solving AB using SOH CAH TOA and primary trig ratios;
AB is the opposite side and AC is the hypotenuse, so we use sin.

sin34 = AB/15
15 • sin34 = AB
8.4 ≈ AB

then, solve for BC

cos34 = BC/15
15 • cos34 = BC
12.4 = BC

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Answer:

(A) Finding the least common denominator.

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Answer:

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3 years ago

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3 years ago

Read 2 more answers

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to