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Simora [160]
4 years ago
13

the Garden Club plants rows of carrots in the garden one seed packet weight 28 grams, round the total weight of two seed packets

to the nearest ten grams
Mathematics
2 answers:
8090 [49]3 years ago
7 0

Answer: 60 grams

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Weight of one seed packet: 28 grams </em>
  • <em>Number of packets: 2 </em>

So, to calculate the total weight of two seed packets we simply have to multiply the weight of each seed packet (28) by the number of packets (2)

Mathematically speaking:

28 x 2 = 56 grams

Rounded to the nearest ten grams = 60 grams

nordsb [41]4 years ago
4 0
The question is first asking us to multiply 28x2, which equals 56. We're going to then round 56 to the nearest ten. The six is greater than five, so we round up,many we're going to round up to 60. So, 60 is your answer.
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Contact [7]

Answer:

Yes

Step-by-step explanation:

Statement                                         Reason

ab = bd                                               Given

ac=cd                                                  Given

bc = cb                                                definiton of reflex line

triangle abc is congruent to triangle dbc      side side side postulate

7 0
3 years ago
Read 2 more answers
Consider the function ​f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0
dybincka [34]

I suppose you mean

f(x)=\cos(x^2)

Recall that

\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}

which converges everywhere. Then by substitution,

\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}

(starting at n=1 because the summand is 0 when n=0)

b. Naturally, the differentiated series represents

f'(x)=-2x\sin(x^2)

To see this, recalling the series for \sin x, we know

\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}

Multiplying by -2x gives

-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}

and from here,

-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}

-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)

c. This series also converges everywhere. By the ratio test, the series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}

The limit is 0, so any choice of x satisfies the convergence condition.

3 0
4 years ago
PLEASE HELP FOR BRAINLIEST!!!
SOVA2 [1]
The measure of an angle<span> formed by a </span>secant<span> and a </span><span>tangent </span><span>drawn from a point outside the </span>circle<span> is half the the difference of the </span>intercepted arcs<span>.

</span>21^o= \frac{arc \ RU-arc \ SU}{2}= \frac{119^o-arc \ SU}{2}  \ \to \ \\ \\ 42= 119-arcSU \\ arc \ SU=119-42=77^o<span>
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5 0
3 years ago
ABCD is a parallelogram AD=10 units AB=8 units AC= 12 units ED= 4.5 unite what is the permitter of ABCD
inna [77]
22 hope it helps 


brainliest?
7 0
3 years ago
Eric is designing a logo for a company. The logo consists of two identical parallelograms joined at their longest sides. One of
Sati [7]

Answer:

A=3.125\ cm^2

Step-by-step explanation:

Given that,

The base of the parallelogram, b = 2.5 cm

Height of the parallelogram, h = 1.25 cm

We need to find the area of the logo. The formula for the area of the parallelogram is given by :

A=b\times h\\\\A=2.5\times 1.25\\A=3.125\ cm^2

So, the area of the logo is 3.125\ cm^2.

8 0
3 years ago
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