Answer:
D. m∠A=43, m∠B=55, a=20
Step-by-step explanation:
Given:
∆ABC,
m<C = 82°
AB = c = 29
AC = b = 24
Required:
m<A, m<C, and a (BC)
SOLUTION:
Find m<B using the law of sines:
m<B = 55°
Find m<A:
m<A = 180 - (82 + 55) => sum of angles in a triangle.
= 180 - 137
m<A = 43°
Find a using the law of sines:
Cross multiply
(approximated)
We divide 40 by 1/2:-
40 / 1/2 = 40 * 2/1 = 80 answer
When it comes to hundreds and thousands and even millions, you can tell how much bigger something is by how many more zeros are at the end. Each new zero added, is another rank up. The system goes:
1=10x bigger
2=100x bigger
3=1000x bigger
4=10000x bigger
5=100000 bigger
so on and so forth. There are 2 zeros in 700, and only 1 zero in 70, the difference in zeros is 1, so you can refer to the chart and conclude that 700 is 10 times bigger than 70. You could also divide 700 by 70 to get 10. This is more accurate, but the chart is simpler.
Answer:
A ----¢ are
B ----¢ are
C ----¢ are
D ----¢ are
E ----¢ aren't
F ----¢ are
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
We have to find the domain of y = cotx
We know that cotx = cos
x / sinx
And also when sinx becomes zero cotx becomes undefined
And again we know that value of cosx and sinx can be between -1 to 1
But value of cotx can lie in between -∞ to +∞
Just for example cot30 is cos30 / sin30
= √3/2/1/2 = √3
Therefore domain of cotx is x
x ∈ R , x ≠ πn for any integer n
