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3 years ago

8 friends share 4 sheets of construction paper equally how much does each person get

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

Each friend gets half a piece of construction paper

Kobotan [32]3 years ago

8 0

4/8=0.5, or 1/2.
Each person would get 1/2 a piece of paper.
Hope this helps.

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The Blair family was one of the first to come to the original 13 colonies (now part of the USA). They had 4 children. Assuming t

Mumz [18]

Answer:

31.25% probability that the Blair family had at least 3 girls

Step-by-step explanation:

For each children, there are only two possible outcomes. Either it was a girl, or it was not. The probability of a child being a girl is independent of any other children. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

They had 4 children.

This means that $n = 4$

The probability of a child being a girl is 0.5

This means that $p = 0.5$

Probability of at least 3 children:

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{4,3}.(0.5)^{3}.(0.5)^{1} = 0.25$

$P(X = 4) = C_{4,4}.(0.5)^{4}.(0.5)^{0} = 0.0625$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 0.25 + 0.0625 = 0.3125$

31.25% probability that the Blair family had at least 3 girls

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3 years ago

Perpendicular lines AB and CD intersect at point E. If m2AED = x+ 20, what is the value of

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Answer:

x = 70

Step-by-step explanation:

Since the lines are perpendicular then ∠ AED = 90°, thus

x + 20 = 90 ( subtract 20 from both sides )

x = 70

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

3. A bag has five blue marbles, seven red marbles and nine green marbles. Three marbles are drawn

Arte-miy333 [17]

Answer:

The probability is 9/266

Step-by-step explanation:

The first thing to do here is get the total number of marbles = 5 + 7 + 9 = 21 marbles

Now we are drawing the marbles without replacement, this means once a marble is drawn there is a decrease in the total number of marbles left.

The probability of drawing a green marble initially = number of green marbles/ total

number of marbles = 9/21 = 3/7

Now, we want to draw a blue marble

There are 5 blue marbles and we have already drawn one marble from the total. So the probability of drawing a blue marble would be 5/20 = 1/4

And lastly, another green marble

That would make 6 green marbles left and a total of just 19 left. So the probability at this point for green marbles = 6/19

Having and in probability means we multiply all

So this means the probability we are calculating is; 3/7 * 1/4 * 6/19 = 18/(28 * 19) = 9/(14 * 19) = 9/266

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Nastasia [14]

Answer:

Step-by-step explanatioen:

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