Answer: are you sure you did ask a question instead of answer it, I’m answering yours like this. Maybe you hit something different. You get points when you answer people. And you use points when you ask a question
Step-by-step explanation:
Answer:
x | x ≥ 0 and x ≤ 8
Step-by-step explanation:
The domain of the function is defined as the possible x values that can be used in this function. Now, taking a look at the given graph, we would find that the line starts from x = 0 and continues taking x values till it reaches x = 0This means that for this function, we are allowed to use x values that are greater than or equal to zero and less than or equal to 8Therefore, the domain is any x value greater than or equal to zero and less than or equal to 8
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
The answer is E histogram
A. 19. You have to set them up equal to each other. So, 6x-2=4x+36. You then subtract the 4x from the 6x, and add 2 to 36. Which leaves you with 2x=38. Divide and you get 19! Hope this helps
