Unit rate would be 50 because 250÷5=50, so the answer would be (250×3)+50, witch is 800.
Answer:
5^8
Step-by-step explanation:
Diego added the exponents. This was an error. If he was simplifying
5^2 × 5^4, then he could add the exponents and get a correct answer. But his problem had a power raised to a power. In this case, you multiply the exponents to simplify.
(5^2)^4 means
5^2×5^2×5^2×5^2
which is
5×5×5×5×5×5×5×5
which is 5^8.
number 9 =al you have to do is one and 7 eighths =9 so your sum will be 10 and 7 eighths.
hope this helps;)
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What kind of operation is this ? it just says x and a nine.
Answer:
x = 2
Step-by-step explanation:
Taking antilogs, you have ...
2³ × 8 = (4x)²
64 = 16x²
x = √(64/16) = √4
x = 2 . . . . . . . . (the negative square root is not a solution)
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You can also work more directly with the logs, if you like.
3·ln(2) +ln(2³) = 2ln(2²x) . . . . . . . . . . . write 4 and 8 as powers of 2
3·ln(2) +3·ln(2) = 2(2·ln(2) +ln(x)) . . . . use rules of logs to move exponents
6·ln(2) = 4·ln(2) +2·ln(x) . . . . . . . . . . . . simplify
2·ln(2) = 2·ln(x) . . . . . . . . . . . subtract 4ln(2)
ln(2) = ln(x) . . . . . . . . . . . . . . divide by 2
2 = x . . . . . . . . . . . . . . . . . . . take the antilogs
