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kirza4 [7]
3 years ago
6

Write an equation of a circle that is centered at (1,-4) with a radius of 10.

Mathematics
2 answers:
alexdok [17]3 years ago
5 0

Answer:

(x-1)^2 + (y+4)^2 = 100\\\\

=====================================================

Work Shown:

(x-h)^2 + (y-k)^2 = r^2\\\\(x-1)^2 + (y-(-4))^2 = 10^2\\\\(x-1)^2 + (y+4)^2 = 100\\\\

You could expand terms out and simplify, but I think it's more handy to leave it in this form so you can easily spot the center and radius from a glance.

tangare [24]3 years ago
4 0

Answer:

Hope this helps!

Step-by-step explanation:

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Write the standard form equation of the line through the given points. through (0.-4) and (-3,-2)
Alexxx [7]

Answer:

The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is \frac{2}{3}x+y=-4

Step-by-step explanation:

The standard form of equation is Ax+By=C

Finding slope

Using the given points (0,-4) and (-3,-2) we can find slope using formula:Slope=\frac{y_2-y_1}{x_2-x_1}

Slope=\frac{-2-(-4)}{-3-(0)}\\Slope=\frac{-2+4}{-3}  \\Slope=-\frac{2}{3}

Finding y-intercept

Using point (0,4) and Slope=-2/3 we can find y-intercept

y=mx+b\\-4=-\frac{2}{3}(0)+b\\-4=0+b\\b=-4

The slope intercept form of the line through the given points. through (0.-4) and (-3,-2) having slope =-2/3 and b=-4 will be:

y=mx+b\\y=-\frac{2}{3}x-4

Now, standard form of equation will be: \frac{2}{3}x+y=-4

So, The standard form of equation of the line through the given points. through (0.-4) and (-3,-2) is \frac{2}{3}x+y=-4

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What is the nineteenth term in the sequence 7, 10, 13, 16, …? A. 64 B. 61 C. 57 D. 19
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Step-by-step explanation:

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Answer:

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