|4r + 8| ≥ 32
4r + 8 ≥ 32 or 4r + 8 ≤ -32 <em> inside of absolute value could be + or -</em>
4r ≥ 24 or 4r ≤ -40 <em>subtracted 8 from both sides</em>
r ≥ 6 or r ≤ -10 <em>divided both sides by 4</em>
Graph: ←---------------- -10 6 ------------------→
Interval Notation: (-∞, -10] U [6, ∞)
Answer:
y = 11
Step-by-step explanation:
We use the definition of Supplementary Angles and Adjacent Angles.
Step 1: Set up equation 1 (Definition of Supplementary Angles)
5x - 4 +7x - 8 = 180
Step 2: Solve for <em>x</em>
12x - 4 - 8 = 180
12x - 12 = 180
12x = 192
x = 16
Step 3: Plug in <em>x</em>
5(16) - 4
80 - 4
76°
Step 4: Set up equation 2 (Definition of Supplementary Angles)
76 + 9y + 5 = 180
Step 5: Solve for <em>y</em>
9y + 81 = 180
9y = 99
y = 11
Answer:
Step-by-step explanation:
Was going to get y’all there in
Its (C) i hope this helps you