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balu736 [363]
1 year ago
6

The transverse axis of a hyperbola is the x-axis, and the equation of the asymptotes is y=± (4)/(3)x

Mathematics
1 answer:
cestrela7 [59]1 year ago
7 0

Given that the transverse axis of a hyperbola is the x-axis, the re-written in the standard form,

a = 3

b = 1

c = 12.

<h3>How do you solve for the standard form of the above equation?</h3>

It is to be noted that the standard form of a linear equation is given as:

ax + by = c

Rewritten in the normal format,

y=± (4)/(3)x ⇒ y-4 = -3 (x-3)

Simplifying -3(x-3) by applying distributive property and we have:
-3x -3 * -3

Hence

y-4 = -3x -3 * -3

⇒ y-4 = -3x + 9

Collecting like terms on one side of the equation we have

3x + y - 4 = 9
⇒ 3x + y = 9+4
⇒ 3x + y = 12 =  Standard Form

Therefore, in standard from,

a = 3

b = 1

c = 12

See the relevant Graph attached.

Learn more about hyperbola at:
brainly.com/question/3405939
#SPJ1

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C) (9, 4)

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4 < 5☑

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Therefore, this solution is genuine.

I am joyous to assist you anytime.

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Amy bought 5lbs., 11oz. Of turkey cold cuts and 6lb., 12 oz. Of ham cold cuts. How much did she buy total? You should convert an
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Each digit 8 in the number 8.888 has a different value placed on its place in the place-value chart. Each 8 is multiplied by its
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Answer:

The value of every digit in a decimal figure is given by its position in that figure.

Step-by-step explanation:

<em>The Rule:</em>

The value of every digit in a decimal figure is given by its position in that figure.

For the figure 8.888, from left to right,

The first 8 is in units

The second 8 is in tenth (this means 8/10 = 0.8)

The third 8 is in hundreth (this means 8/100 = 0.08)

The fourth 8 is in thousandth (this means 8/1000 = 0.008)

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3 years ago
Which value is equivalent to 7 to the 3rd power
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4 0
2 years ago
Suppose that f(x,y) is a smooth function and that its partial derivatives have the values, fx(−7,−2)=−1 and fy(−7,−2)=3. Given t
yarga [219]

Answer:

f(-6,-1) =0

Step-by-step explanation:

We are given the following in the question:

f_x(-7,-2)=-1\\f_y(-7,-2)=3\\f(-7,-2)=-2

We have to estimate the value of f(-6,-1)

By Taylor approximation we have:

f(x,y) =f(-7,-2)+ f_x(-7,-2)(x+7) + f_y(-7,-2)(y+2)\\f(x,y) = -2 + (-1)(x+7) + 3(y+2)\\f(x,y) = -2-x-7+3y+6\\f(x,y) = -x+3y-3

Now, putting values, we get,

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is the required value.

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3 years ago
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