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1 year ago

The transverse axis of a hyperbola is the x-axis, and the equation of the asymptotes is y=± (4)/(3)x

Mathematics

1 answer:

cestrela7 [59]1 year ago

7 0

Given that the transverse axis of a hyperbola is the x-axis, the re-written in the standard form,

a = 3

b = 1

c = 12.

<h3>How do you solve for the standard form of the above equation?</h3>

It is to be noted that the standard form of a linear equation is given as:

ax + by = c

Rewritten in the normal format,

y=± (4)/(3)x ⇒ y-4 = -3 (x-3)

Simplifying -3(x-3) by applying distributive property and we have:
-3x -3 * -3

Hence

y-4 = -3x -3 * -3

⇒ y-4 = -3x + 9

Collecting like terms on one side of the equation we have

3x + y - 4 = 9
⇒ 3x + y = 9+4
⇒ 3x + y = 12 = Standard Form

Therefore, in standard from,

a = 3

b = 1

c = 12

See the relevant Graph attached.

Learn more about hyperbola at:
brainly.com/question/3405939
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Read 2 more answers

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are

skelet666 [1.2K]

A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at $55, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

p(2400)=300−(2400/20)=180

profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at $55, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

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1 year ago