The transverse axis of a hyperbola is the x-axis, and the equation of the asymptotes is y=± (4)/(3)x
1 answer:
Given that the transverse axis of a hyperbola is the x-axis, the re-written in the standard form,
a = 3
b = 1
c = 12.
<h3>How do you solve for the standard form of the above equation?</h3>It is to be noted that the standard form of a linear equation is given as:
ax + by = c
Rewritten in the normal format,
y=± (4)/(3)x ⇒ y-4 = -3 (x-3)
Simplifying -3(x-3) by applying distributive property and we have:
-3x -3 * -3
Hence
y-4 = -3x -3 * -3
⇒ y-4 = -3x + 9
Collecting like terms on one side of the equation we have
3x + y - 4 = 9
⇒ 3x + y = 9+4
⇒ 3x + y = 12 = Standard Form
Therefore, in standard from,
a = 3
b = 1
c = 12
See the relevant Graph attached.
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Answer:
Step-by-step explanation:
Remark
Always the easiest way to study these questions is to get a graph. The one below shows
Red: y = x^2
Blue: y= 3(x + 1)^2
You will notice that (x+1)^2 shifts the graph Left -- the opposite to what you might think.
The 3 is a little harder. It narrows the red mother graph. Which choice says that?
The choice is between b and d. Why. Because the blue graph is to the left of the red one.
You have to learn the meaning of compressed. A better word might be narrows.
Answer
B
