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Triss [41]
3 years ago
6

Isla used her computer for 5 hours over the weekend. How many minutes did she spend on the computer?

Mathematics
2 answers:
natulia [17]3 years ago
8 0

Answer: 300

Step-by-step explanation:

Sonbull [250]3 years ago
6 0

Answer:

300 minutes

Step-by-step explanation:

5x60=300.

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What is the interquartile range of this data?<br><br><br> 5<br><br> 8<br><br> 13<br><br> 17
Tanya [424]

Lowest value: 2

Highest value: 19

Median: 8

Lower quartile: 6

Upper quartile: 14

Range: Highest value - Lowest value = answer

Range: 19 - 2 = 17

Interquartile range: Upper quartile - Lower quartile = answer

(IQR) interquartile range = 14 - 6 = 8

So the answer to your question would be 8 :)

~hope this helps, have a good day/afternoon/night~

5 0
3 years ago
-3y^10-5y^14: Write in standard form, find the degree, and classify the number of terms
alisha [4.7K]

Answer:

STANDARD: -5y^14 -3y^10

DEGREE: 14

NUMBER OF TERMS: 2

Step-by-step explanation:

Two terms, the highest degree is 14, and standard has the term with the highest degree in the front.

7 0
3 years ago
The drain in your 45-gallon bathtub is partially clogged, but you need to take a shower. The shower head had a flow rate of 2.25
Helen [10]

Answer:

Time = 1.978\ min

Step-by-step explanation:

Given

R_1 = 2.25\ gal/min --- Flow rate of the shower

R_2 = 20.5\ gal/min --- Drain rate of the bathtub

Size = 45gal -- Bathtub size

Required

Determine the maximum time of shower

First, we calculate the rate at which the bathtub fills.

R_3 = R_1 + R_2

R_3 = 2.25 + 20.5

R_3 = 22.75gal/min

The maximum time of shower is:

Time = \frac{Size}{R_3}

Time = \frac{45gal}{22.75gal/min}

Time = 1.978\ min  

6 0
3 years ago
Let f(x) = x^2 - 11x - 60.<br> Solve for f(x) using factoring.
Alona [7]
F(x) = X^2 - 11x - 60
Two terms that multiply to -60 and add to -11 so...
F(x) = (X - 15) (x + 4)
Your x-intercepts would be 15 and -4.
4 0
3 years ago
The world's heaviest man is reported to have had a mass of 635 kg what was his weight
nataly862011 [7]

Answer:

about 6230 N

Step-by-step explanation:

The mass is given to 3 significant figures, so we need a value for the acceleration due to gravity that is at least 3 significant figures. The standard value is 9.80665 m/s². Using that, the force is ...

... F = ma = (635 kg)(9.80665 m/s²) = 6227.22275 N

Since the mass is only good to 3 significant figures, the force must be rounded to that precision: 6230 N.

3 0
3 years ago
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