What is 19 over 57 in simplest form

Mathematics

1 answer:

JulijaS [17]4 years ago

5 0

19/57 in simplest form is 1/3 and is 0.333 in decimal form

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If the unicorn seat on a merry–go–round is 5 feet from the center, and the merry–go–round completes a full rotation in 6 seconds

Cerrena [4.2K]

The answer is 5.23 ft/second

The way I got this answer was first finding the circumference of the merry-go-round using the equation $C=2 \pi r$ , where r represents the radius, which is the distance from the center of a circle.

So your equation should look like this $C=2 \pi(5)$ . I used the rounded term of 3.14 for $\pi$

Once you multiply those terms, you should get the answer, 31.4. Now this is the total distance around the merry-go-round in feet. So, if it takes 6 seconds to make a full rotation and we are trying to find the amount offeet traveled in one second, we should divide the circumference (31.4) by 6 to give us our answer.

So, 31.4÷6=5.2333...ft/second

And I rounded the answer to the nearest hundredth to get 5.23 feet/second

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3 years ago

Read 2 more answers

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Alex Ar [27]

$5 each car 3 hours = 12 cars ÷3 ÷3 1 hours = 4 cars ×8 ×8 8 hours = 32 cars 32 cars × $5 per car = $160 They earned $160 in 8 hours, from washing 32 cars.

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3 years ago

An object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seco

bulgar [2K]

Answer:

$y=2\text{cos}((\frac{2\pi}{3})t)$

Step-by-step explanation:

We have been given that an object oscillates 4 feet from its minimum height to its maximum height. The object is back at the maximum height every 3 seconds. We are asked to find the cosine function that can be used to model the height of the object.

We know that standard form of cosine function is $y = A\cdot \text{cos}(Bt-C)+D$ , where,

|A| = Amplitude,

Period = $\frac{2\pi}{|B|}$ ,

C = Phase shift,

D = Vertical shift.

Since distance between maximum and minimum is 4, therefore, amplitude will be half of it, that is, $A = 2$ .

Since objects gets back to its maximum value in every 3 seconds, therefore, period of the function is 3 seconds. We know that period is given by $\frac{2\pi}{|B|}$ , therefore, we can write $\frac{2\pi}{|B|}=3$ , therefore, $B = \frac{2\pi}{3}$ .