Dave is riding on a straight path. After 5 s, his speed is 3.0 m/s. After 7 s, his speed is 5.0 m/s. After 10 s, his speed is 7. 0 m/s. What was his acceleration from 5 s to 10 s? A. 0.67 m/s2 B. 1.0 m/s2 C. 2.0 m/s2 D. 0.8 m/s2
       
      
                
     
    
    
    
    1  answer:
            
              
In this given problem, to solve for the acceleration we have to
assume that the acceleration is constant. This assumption helps us understand
that the velocity of Dave follows a linear increase and hence we can use the
formula below for calculating the acceleration:
a= (Vf – Vi) / t
where
Vf = final velocity = 7.0 m / s
Vi = intial velocity = 3.0 m / s
t = time elapsed = 10 s – 5 s = 5 s
Substituting the known values into the equation:
a = (7.0 m / s – 3.0 m / s) / 5 s
a = 0.8 m / s^2
 
Answer: 
 <span>D. 0.8 m/s2 </span>
 
                                
             
         	
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