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3 years ago

Winifred has run 5% of a race so far. She has now run 1.38km, how long is the race?

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Answer:

race run = 27.60 km

Step-by-step explanation:

given data

run = 5 %

race = 1.38 km

to find out

how long is the race

solution

we get here how long he race that is here

1.38 ÷ 5 % × 100

= 20

race run = 1.38 × 20

race run = 27.60 km

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Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

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Answer:

(3,4,5)

(6,8,10)

(5,12,13)

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(12,16,20)

(7,24,25)

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Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

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So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

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$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

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$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

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Another Pythagorean Triple is (16,30,34).

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$(41)^2=(9)^2+(40)^2$

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3 years ago

Tell whether the value is a solution of the inequality X=36; 3x<100

sladkih [1.3K]

Answer:

x = 36 is not a solution

Step-by-step explanation:

3x<100

Let x = 36

3*36 < 100

108 < 100

This is not true so x = 36 is not a solution

8 0

2 years ago

Read 2 more answers