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3 years ago

I'm so confused please help

Mathematics

2 answers:

Darya [45]3 years ago

8 0

Answer:

84.3%

Step-by-step explanation:

Total frequency is the total area:

Add all the areas

To find each area:

Frequency density × class width

Total frequency:

40×10 + 30×10 + 25×20 + 15×5

= 1275

Less than 40:

Bar 1 + Bar 2 + some part of Bar 3

40×10 + 30×10 + 25×15

= 1075

Percentage (<40) = 1075/1275 × 100

= 4300/51

= 84.31372549%

Hatshy [7]3 years ago

6 0

I'm confused too and I'm supposed to be an expert. I'm not entirely sure what frequency density is. We'll just treat this as a histogram.

Let's assume each five minute interval gives a value equal to or proportional to the number of people that finished in that interval.

From 0 to 50 we have 10 intervals; let's just make this into a table

0-5 0

5-10 40

10-15 40

15-20 30

20-25 30

25-30 25

30-35 25

35-40 25

40-45 25

45-50 15

From 0 to 40 that adds up to

0+40+40+30+30+25+25+25 = 215

From 0 to 50 that's

215+25+15 = 255

The fraction less than 40 is 215/255 = 43/51 ≈ .843

Answer: 84.3%

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6 m

dimulka [17.4K]

Answer:

51.63m^3

Step-by-step explanation:

The figure is made up of a rectangle, triangle and a semi circle

Area of the figure = Area of triangle + rectangle + semicircle

Area of the triangle = 1/2 * base * height

Area of the triangle = 1/2 * 3 * 5

Area of the triangle = 15/2

Area of the triangle = 7.5m^3

Area of the rectangle = Length * Width

Area of the rectangle = 6 * 5

Area of the rectangle = 30m^2

Area of the semicircle = πr²/2

Area of the semicircle = π(3)²/2

Area of the semicircle = 3.14(9)/2

Area of the semicircle = 3.14 * 4.5

Area of the semicircle = 14.13m^2

The area = 30 + 14.13+7.5

Area of the figure = 51.63m^3

7 0

3 years ago

Read 2 more answers

The answer for this problem

ElenaW [278]

Only the 3. option can be used. All other values dont fit

4 0

3 years ago

If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a yea

Natasha2012 [34]

Answer:

$P(Atleast\ 1) = 0.9999992$

Step-by-step explanation:

Given

$p = 3\%$ --- rate of hard disk drives failure

$n = 4$ --- number of hard disk drives

<em>See comment for complete question</em>

Required

$P(Atleast\ 1)$

First, calculate the probability that the none of the 4 selected is working;

$P(none) = p^4$

$P(none) = (3\%)^4$

$P(none) = (0.03)^4$

Using the complement rule, the probability that at least 1 is working is:

$P(Atleast\ 1) = 1 - P(none)$

This gives:

$P(Atleast\ 1) = 1 - 0.03^4$

$P(Atleast\ 1) = 0.9999992$

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3 years ago

Explain step by step.

Ahat [919]

X=5 y=60
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3 years ago

How many times can 3 go in to 579

givi [52]

193 times hope this helps

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3 years ago