First find the square root 4x^-6= 2x^-3 9y^-4= 3y^-2 If a negative exponent is in the numerator, move the expression to the denominator and make the exponent positive So instead of 2x^-3/3y^-2 make it 2y^2/3x^3 So The answer will be 2y^2/3x^3 Hope this helps
