There are 3 ways of solving a simultaneous problem, substitution method, elimination method and Gauss-Jordan method. I'm gonna use the substitution method since it's easier and i think it would suit your level more.

First let's try solving for y since it's easier to start with.

Firstly we have to find an equation for x:

$x-2y=2\\x-2y+2y=2+2y\\x=2+2y$

Great, now we can use the substitution method to find the value of y using the first equation:

$2x+3y=11\\2(2+2y)+3y=11\\4+4y+3y=11\\7y=7\\y=1$

Now we know that y=1 we can solve the first equation we made:

$x=2+2y\\x=2+2(1)\\x=4$

And the answer is $x=4 , y= 1\\(4,1)$

Double check:

$2x+3y=11\\2(4)+3(1)=11\\8+3=11\\11=11\\\\x-2y=2\\(4)-2(1)=2\\2=2$

And that's our final answer! (4,1)

7 0

3 years ago

I need help for number 49

Dmitry_Shevchenko [17]

I'm thinking it's B for that question

8 0

3 years ago

Paul has 7 piles of sports cards. There are3 basketball. football. and4 baseball cards in each pile. How many total sports cards

aalyn [17]

Paul has 70 Total sport cards.

3 (Baseball) + 3 (Football) + 4 (Baseball) = 10 (Total cards per pile) × 7 (Total Piles) = 70 (Total Cards

3+3+4=10×7=70

(All shown work is this ^)

If I'm right please help me out by following me. Thank you for your wonderful question~!

8 0

3 years ago

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