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3 years ago

Use the net as an aid to compute the surface area of the triangular prism.

Mathematics

1 answer:

Ray Of Light [21]3 years ago

3 0

Answer:

790

Step-by-step explanation:

i just took the test

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2x-7=117 what is the value of x

Tcecarenko [31]

$2x - 7 = 117$

Add 7 to both sides

$7 + 2x - 7 = 117 + 7$

At the left hand side 7 will cancel 7

At the right hand side 7 will add up

$2x = 124$

Divide through by 2

$x = \frac{124}{2}$

simplify the fraction

$x = 62$

4 0

2 years ago

4) Use the distance formula to find the length of segment BC.

gogolik [260]

Answer:

Step-by-step explanation:

d= √(5-1)^2+(1-4)^2

d= √4^2+(-3)^2

d= √16+9

d=√25

d=5

8 0

3 years ago

Please help me to find the answer Y=2X 3X+4Y=22 Y=2X 3X+4Y=22

RSB [31]

<h3>System of equations.</h3>

$\left\{\begin{array}{ccc}y=2x&(1)\\3x+4y=22&(2)\end{array}\right$

Put (1) to (2):

$3x+4(2x)=22\\3x+8x=22\\11x=22\qquad|\text{divide both sides by 11}\\\boxed{x=2}$

Substitute the value of x to (1):

$y=2\cdot2\\\boxed{y=4}$

Solution:

$\huge\boxed{\left\{\begin{array}{ccc}x=2\\y=4\end{array}\right}$

7 0

1 year ago

Please answer this correctly

sesenic [268]

Answer:

Step-by-step explanation:

The sorted data set is ...

1 2 3 3 5 7 8 9

The median is the average of the middle two numbers: (3+5)/2 = 4.

Replacing one of the 3s with a 1 makes the data set be ...

1 1 2 3 5 7 8 9

The average of the middle two numbers is (3+5)/2 = 4.

The median increases by 4 - 4 = 0.

7 0

3 years ago

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

$P(B|A) = \frac{12}{51}$

What is the probability of choosing a king and then, without replacement, a face card?

$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.

5 0

3 years ago