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3 years ago

Solve (200 + 200) √100

Mathematics

2 answers:

mart [117]3 years ago

4 0

Answer:

4000

Step-by-step explanation:

200 + 200 {100

400 × 10

4000

Bogdan [553]3 years ago

3 0

Answer:

4000

Step-by-step explanation:

because the 200+200 are in parenthesis that shows that you will need to do it first.

so.. 200+200=400

and now the second part is asking for the square root of 100. We know that 10 times 10 is 100. This means that 10 is the square root of 100.

And for our last step they ask to multiply our two answers.

so 400 x 10= 4000

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Find the solution of this system of equations. Separate the x and y values with a comma.

Serga [27]

Ok so in solving systems of linear equations, we first find the value of a variable. By looking at the equations, solving for x by using the second equation seems the easiest.

x - y = -5

x = -5 + y

x = y - 5

Then we plug in the equation of x into the first equation and solve for y.

x - 2y = 19

y - 5 - 2y = 19

-3y - 5 = 19

-3y = 24

-y = 8

y = -8

Now we plug in y = -8 in the solved equation for x

x = y - 5

x = -8 - 5

x = - 13

Therefore, x = -13 and y = -8

Hope this helps!

4 0

3 years ago

Read 2 more answers

Solve the system of equations

kaheart [24]

Answer:

x=-12,y=3

Step-by-step explanation:

1/2x+6y=12

y=x+15

since y=x+15

substitute y in first equation, we have

1/2x+6(x+15)=12

open the bracket

1/2x+6x+90=12

1/2x+6x=12-90

x/2+6x= -78

13x/2=-78

13x=2×-78

x=-12

Now x=-12, put x=-12 in the second equation, we have

y=x+15

y=-12+15

y=3

hope it helps

3 0

2 years ago

Read 2 more answers

Find the value of g(25) for the function below. g(x)=24(x-39)

djverab [1.8K]

G(x) = -336
That is the answer

5 0

4 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$