Answer:
x=2.11872822
Step-by-step explanation:
The explorer's running velocity will be 1/3 the velocity of the train, 45/3 = 15.
From those issue statement, the train will a chance to be at the begin of the span The point when those voyagers have run 1/3 of the period of the span. In they run of the much end of the bridge, they will bring run 1/3 of the length of the span when those prepare achieves the close to wind. Beginning starting with those 1/3 point, they will make toward those 2/3 perspective At those prepare achieves those span. The prepare will travel the full period of the span in the the long haul it takes those voyagers to run those remaining 1/3. Accordingly the train must travel toward three times the running speed of the voyager. Train = 45 mph, voyagers = 15 mph.
The speed of P&D = 15 mph
Answer:
a) 625
b) Yes
c) No
Step-by-step explanation:
a)To calculate the maximum height we can use the derivative to find the slope of the function.

To find the slope we make the equation equal to 0:


The slope at 0 is t=200/32=6.25[/tex]
The maximum height at t=6.25 is

The maximum height is 625
b) at t=8

The height will be 576 which is less than 625
The two x-intercepts are when h=0:
c)






The ball is not in the air because the ball will only be in the air from t=0 to t=12.5