Answer:
The inequality for each quantity described is given as follows;
0 ≤ A + B + C + D + E ≤ 50
Step-by-step explanation:
The given information are;
The number of players each team can have = between 3 and 5
The maximum number of points a player can score in each round of the game = 10 points
The number of players in Elena's team = Elena + 4 = 5 players
The total number of points Elena's team earns at the end of the round is given as follows;
0 ≤ A + B + C + D + E ≤ 5 × 10
Where the variables A, B, C, D, and E are the points each of Elena and are makes such that the minimum points is 0 + 0 + 0 + 0 + 0 = 0 and the maximum point is 10 + 10 + 10 + 10 + 10 = 5 × 10 = 50, which gives;
0 ≤ A + B + C + D + E ≤ 50.
Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
the answer to the question is = (x = 1)
Answer:
Help me with my question
Step-by-step explanation:
<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em><em>7.96 Ω.</em>
<u>Solution-</u>
Two capacitors, a 20 mF and a 30 mF, are connected in parallel to a 400 Hz source.
The effective/equivalent capacitance of the circuit is,

As, when capacitors are connected together in parallel, the equivalent capacitance in the circuit is equal to the sum of capacitance of all the individual capacitor.
We know that,

Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 400 Hz
C = 50 mF =
F
Putting the values in the formula,



Therefore, the total capacitive reactance of the circuit is 7.96 Ω.