3 years ago

Which is the correct answer?

Mathematics

1 answer:

Crazy boy [7]3 years ago

8 0

C because I said
So
Lol
Ahahha
Goggle

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The markup on a restaraunt meal is 250%. A meal costs $7.30 to produce. How much will the customer be charged before tax and tip

Anarel [89]

Answer:

$25.55

Step-by-step explanation:

7.30*2.50=18.25

7.30+18.25=25.55

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2 years ago

Number 23 I have no clue

kipiarov [429]

B. Write an equation

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A candy maker had a piece of taffy that was 53 inches long. If he chopped it into 6 equal length pieces, how long would each pie

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3 years ago

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If f(x) = 3x + 2, what is f(5)?

Volgvan

Answer:

The 5 in the () is what the x is

Step-by-step explanation:

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3 years ago

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For the following telescoping series, find a formula for the nth term of the sequence of partial sums

gtnhenbr [62]

I'm guessing the sum is supposed to be

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}$

Split the summand into partial fractions:

$\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}$

$1=a(5k+4)+b(5k-1)$

If $k=-\frac45$ , then

$1=b(-4-1)\implies b=-\frac15$

If $k=\frac15$ , then

$1=a(1+4)\implies a=\frac15$

This means

$\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}$

Consider the $n$ th partial sum of the series:

$S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)$

The sum telescopes so that

$S_n=\dfrac2{14}-\dfrac2{5n+4}$

and as $n\to\infty$ , the second term vanishes and leaves us with

$\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17$

7 0

3 years ago