Answer:
b
Step-by-step explanation:
Answer:
infinite
Step-by-step explanation:
1/6 of 12 is 2
1/6 of 18 is 3
Plug them in
2z-3=2z-3
meaning you can put literally any number in place of z and it'd work.
For implicit differentiation, you are using the chain rule

Except u(x) = y, So after every "y" term is differentiated it will be multiplied by dy/dx.
17)

Then you solve for dy/dx as if its a variable.

18) Here lets review product rule:

Take derivative of each term

Solve for dy/dx using factoring:
1/4= 0.25
2/4= 1/2 = 0.5
0.25 x 0.5 = 0.125
0.125 = 1/8
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2