Availability of first truck probability P (1) = 0.74
Availability of second truck probability P (2) = 0.57
Availability of both truck probability P (1 and 2) = 0.46
So the probability of at least one available P (1 or 2) = P (1) + P (2) - P (1 and 2) = 0.74 + 0.57 - 0.46 = 0.85
Now the probability of at neither available = 1 - P (1 or 2) = 1 – 0.85 = 0.15
Answer:
y = 2/3 x - 3
Step-by-step explanation:
substitute the given slope and the coordinate into the slope-intercpet form:
y = mx + b to solve for b,
-1 = 2/3(3) + b
=> b = -3
y = 2/3 x - 3
Answer: 0.7257
Step-by-step explanation:
Given : The weights of steers in a herd are distributed normally.
Standard deviation : 
Let x be the weight of the randomly selected steer .
Z-score : 

The the probability that the weight of a randomly selected steer is greater than 920 lbs using standardized normal distribution table :
Hence, the probability that the weight of a randomly selected steer is greater than 920lbs =0.7257
Answer:
h=4
Step-by-step explanation:
5²-3²=h²
h²=16
h=4cm