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3 years ago

A right cylinder has a radius of 2 units and a height of 5

Mathematics

2 answers:

erica [24]3 years ago

6 0

Answer:

62.8

Step-by-step explanation:

The volume of the cylinder is = base * height

base=Pi*radius*radius, where

base=3.1416*2*2 , height=5

Volume=3.1416*2*2*5

Volume =62.8 cubic units.

mamaluj [8]3 years ago

5 0

Answer:

Option B.

Step-by-step explanation:

It is given that right cylinder has a radius of 2 units and a height of 5 units. It means

r = 2

h = 5

The volume of a right cylinder is

$V=\pi r^2h$

where, r is radius and h is height of the cylinder.

Substitute r=2 and h=5 in the above formula.

$V=\pi (2)^2(5)$

$V=\pi (4)(5)$

$V=20\pi$

On further simplification we get

$V=62.831853$

$V\approx 62.8$

The volume of right cylinder is 62.8 cubic units.

Therefore, the correct option is B.

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20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

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<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

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Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

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First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

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