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joja [24]
3 years ago
8

A snail can travel 390 inches in 5 hours. How far does it travel in 1 hour?

Mathematics
2 answers:
puteri [66]3 years ago
8 0
78, divide 390 by 5 which equals 78
seraphim [82]3 years ago
7 0

Answer:

78 inches

Step-by-step explanation:

5 hours = 390 inches

1 hour = 390 / 5

1 hour = 78 inches

Therefore <u>the snail travels 78 inches in 1 hour.</u>

Hope this helps!

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Complete the point-slope equation of the line through (3,6)(3,6)left parenthesis, 3, comma, 6, right parenthesis and (5,-8)(5,−8
ArbitrLikvidat [17]

Answer:

The required equation of line in point-slope form is:

y-6 = -7(x-3)

Step-by-step explanation:

Given points are:

(x1,y1) = (3,6)

(x2,y2) = (5,-8)

The point-slope form of an equation is given by:

y-y_1 = m(x-x_1)

Here m is slope of the line and (x1,y1) is a point on line

The slope is calculated using the formula:

m = \frac{y_2-y_1}{x_2-x_1}

Putting the values we get

m = \frac{-8-6}{5-3}\\m=\frac{-14}{2}\\m= -7

Putting in the equation

y-y_1 = -7(x-x_1)

Now we have to put a point in the equation, putting (3,6) in the equation

y-6 = -7(x-3)

Hence,

The required equation of line in point-slope form is:

y-6 = -7(x-3)

5 0
3 years ago
How many 3 digit palindromes are divisible by 9?
ludmilkaskok [199]

Interesting problem.

A palindrome is a number which is identical when read/interpreted left-to-right or right-to-left.   For example, 14241 is a palindrome, so is 444444.


A three digit palindrome must be made up of two distinct digits only, one for the first and last digits, and one for the middle, for example, 424, or 515, etc.


For a number to be divisible by 9, the sum of the digits must add up to a multiple of 9, such as 0, 9, 18, 27, etc.


We can now form a table of the possible 3-digit palindromes divisible by 9, starting with the first/last digits (=A), and finding the middle digit (=B).  The number is therefore represented by the pattern ABA.

For example, when A=1, we have the number 1B1.  For the number to be divisible by 9, B=7 so that sum=1+7+1=9, which is divisible by 9.

For each value of A (from 1 to 9) we can only find one value of B that makes the number divisible by 9.   Thus we can only find nine such numbers, with A equal to 1 to 9.

Here's a list of the numbers

A   B   number

1    7    171

2   5    252

3   3    333

4   1     414

5   8    585

6   6    666

7   4    747

8   2   828

9   0   909

3 0
3 years ago
Half of the students in Max's class volunteer at the local community center. Fifteen students do not volunteer. If there are 12
ella [17]

Answer:

18

Step-by-step explanation:

15 x 2 = 30

30 - 12 = 18

18 girls are in his class

5 0
3 years ago
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What is this Method???
Rina8888 [55]
Standard algorithm i think 
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3 0
3 years ago
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I am having trouble with this relative minimum of this equation.<br>​
Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach.  You have to let me know if you want this done another way.

Here are some rules I'm going to use:

(f+g)'=f'+g'       (Sum rule)

(cf)'=c(f)'          (Constant multiple rule)

(x^n)'=nx^{n-1} (Power rule)

(c)'=0               (Constant rule)

(x)'=1                (Slope of y=x is 1)

y=4x^3+13x^2-12x-56

y'=(4x^3+13x^2-12x-56)'

y'=(4x^3)'+(13x^2)'-(12x)'-(56)'

y'=4(x^3)'+13(x^2)'-12(x)'-0

y'=4(3x^2)+13(2x^1)-12(1)

y'=12x^2+26x-12

Now we set y' equal to 0 and solve for the critical numbers.

12x^2+26x-12=0

Divide both sides by 2:

6x^2+13x-6=0

Compaer 6x^2+13x-6=0 to ax^2+bx+c=0 to determine the values for a=6,b=13,c=-6.

a=6

b=13

c=-6

We are going to use the quadratic formula to solve for our critical numbers, x.

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}

x=\frac{-13 \pm \sqrt{169+144}}{12}

x=\frac{-13 \pm \sqrt{313}}{12}

Let's separate the choices:

x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}

Let's approximate both of these:

x=0.3909838 \text{ or } -2.5576505.

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

f(x)=4x^3+13x^2-12x-56

f'(x)=12x^2+26x-12

f''(x)=24x+26

So if f''(a) is positive then we have a minimum at x=a.

If f''(a) is negative then we have a maximum at x=a.

Rounding to nearest tenths here:  x=-2.6 and x=.4

Let's see what f'' gives us at both of these x's.

24(-2.6)+25

-37.5  

So we have a maximum at x=-2.6.

24(.4)+25

9.6+25

34.6

So we have a minimum at x=.4.

Now let's find the corresponding y-value for our relative minimum point since that would complete your question.

We are going to use the equation that relates x and y.

I'm going to use 0.3909838 instead of .4 just so we can be closer to the correct y value.

y=4(0.3909838)^3+13(0.3909838)^2-12(0.3909838)-56

I'm shoving this into a calculator:

y=-58.4654411

So the approximate relative minimum is (0.4,-58.5).

If you graph y=4x^3+13x^2-12x-56 you should see the graph taking a dip at this point.

3 0
3 years ago
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