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vagabundo [1.1K]
3 years ago
14

Two poles, A and B, are 12 meters apart. Pole A is 5 meters high. A rope 20 meters long is tied to the top of pole A and stretch

es to the top of pole B. What is the height of pole B? Assume that pole B is taller than pole A.

Mathematics
2 answers:
inna [77]3 years ago
5 0
Let the height of pole B be x meters.

We have a right angled triangle  whose base = 12 m , hypotenuse = 20 m  and height = (x - 5) m.

Applying the pythagoras theorem:-

20^2 = (x - 5)^2 + 12^2

x^2 - 10x + 25  = 20^2 - 12^2

x^2 - 10x + 25 =  256

x^2 - 10x - 231 = 0

(x - 21)(x + 11) = 0

x = 21, -11    We ignore the negative root

So the Pole B is 21 meters high.  Answer

e-lub [12.9K]3 years ago
4 0

Answer: The height of the pole will be 21 m.

Step-by-step explanation:

Since we have given that

Length of pole A = 5 meters

Distance between Pole A and Pole B = 12 m

Length of rope is tied to the top of pole A and stretches to the top of pole B = 20 meters

As shown in the figure below , we can apply "Pythagorus theorem" to find the height of the topper part of triangle :

H^2=B^2+P^2\\\\20^2=12^2+B^2\\\\400=144+B^2\\\\400-144=B^2\\\\256=B^2\\\\\sqrt{256}=B\\\\16=B

So, Length of pole B will be

16+5=21\ m

Hence, the height of the pole will be 21 m.

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