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Elza [17]
3 years ago
10

a lawnmower manufacturer has the following loss distribution for its annual products liability costs: loss probability 250,000 0

.05 10,000 0.15 0 0.9 what is the expected claim cost for a policy with $10,000 deductible
Business
1 answer:
Bas_tet [7]3 years ago
6 0

Answer: $12,000

Explanation:

The question makes no sense in one area. The loss probability for $0 cannot be 90% because the other two are collectively 20%. I shall therefore assume that the loss probability for $0 is 80% so that they add up to 100%.

Expected claim cost = ∑[loss probability * (Loss - Deductible)]

= 0.9 * 0 + [0.15 * (10,000 - 10,000)] + [0.05 * (250,000 - 10,000)]

= $12,000

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If the price charged for a candy bar is p cents, then x thousand candy bars will be sold in a certain city, where p = 8 - . how
coldgirl [10]

992 candy bars must be sold to maximize revenue.

<h3>What is revenue?</h3>
  • The total amount of income generated by the sale of goods and services related to the primary operations of the business is referred to as revenue in accounting.
  • Commercial revenue is also known as sales or turnover.
  • Some businesses make money by charging interest, royalties, or other fees.

To find how many candy bars must be sold to maximize revenue:

The price of a candy bar is determined by the quantity sold:

  • p(x) = 124 - (x/16) where x is in 1000s.

If the candy bar's price is p(x), the revenue function is:

  • R(x) = p(x) · x = 124 · x - x²/16

Find the solution of R'(x) = 0 to maximize R(x):

  • R'(x) = 124 - x/8
  • 124 -  x/8 = 0
  • x = 992

Therefore, 992 candy bars must be sold to maximize revenue.

Know more about revenue here:

brainly.com/question/25623677

#SPJ4

The correct question is given below:
If the price of a candy bar is p(x) cents then x thousand candy bars are sold. The price p(x) = 124-(x/16). How many candy bars must be sold to maximize revenue?

6 0
1 year ago
An asset has an average return of 10.94 percent and a standard deviation of 20.98 percent. What range of returns should you expe
valkas [14]

If the standard deviation is 20.98%. The range you should expect to see with a 95 percent probability is: -31.02 percent to +52.9 percent.

<h3>Expected range of return </h3>

Expected range of return = 10.94 percent ± 2(20.98 percent)

Expected range of return =[10.94 percent- 2(20.98 percent)]; [10.94 percent + 2(20.98 percent)]

Expected range of return =(10.94 percent- 41.96 percent); (10.94 percent + 41.96 percent

Expected range of return = -31.02 percent to +52.9 percent

Inconclusion the range of returns is: -31.02 percent to +52.9 percent.

Learn more about expected range of return here:brainly.com/question/25821437

8 0
2 years ago
If an individual investor uses the services of a broker to buy and sell stocks that are currently being traded in the stock mark
sergejj [24]

Answer:

a. False

Explanation:

A "primary transaction" refers to the selling of <em>new stocks and bonds</em> for the first time towards the public. A great example of this is the "Initial Public Offering" <em>(IPO)</em> which allows "public share issuance."

On the other hand, a "secondary transaction" refers to the<em> trading of investors among themselves.</em> There is no involvement of the issuing companies here. So, this means that if an investor uses the services of a broker to buy and sell stocks that are currently being traded in the stock market,<u> the transaction</u><u> doesn't directly involve the issuing compan</u><u>y.</u> This kind of transaction is then called "secondary."

So, this explains the answer.

8 0
2 years ago
For a binomial experiment with r successes out of n trials, what value do we use as a point estimate for the probability of succ
trapecia [35]

Answer: \dfrac{r}{n}

Explanation:

If r is the number of successes out of n trials , then the sample proportion of success = \hat{p}=\dfrac{r}{n}

For binomial experiment , if the population probability of success p on a single trial is not given , then the best point estimate for probability of success p on a single trial is the sample proportion of successes.

i.e. a point estimate for the probability of success p on a single trial :

p=\hat{p}=\dfrac{r}{n}

Hence, a point estimate for the probability of success p on a single trial = \dfrac{r}{n}

4 0
3 years ago
Question 2 of 20
aleksklad [387]

I guess the answer is C. to convince your manager to use a new meeting organization tool

8 0
2 years ago
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